Question

The age of the father is 3 year more than three times age of the son 3 year hence father's age will be 10 year more than twice the age of his son .find there present age ( take 2 variables)​

Answer 1

Solution :

Let the son's age be r years.

Let the father age be 3r + 3 years

A/q

$\underbrace{\sf{After\:3\:years\::}}}}$

The son's age will be = (r + 3) years.

The father's age will be = (3r + 3 + 3) years.

Now;

$\longrightarrow\sf{3r+3+3=10+2(r+3)}\\\\\longrightarrow\sf{3r+6=10+2(r+3)}\\\\\longrightarrow\sf{3r+6=10+2r+6}\\\\\longrightarrow\sf{3r+6=2r+16}\\\\\longrightarrow\sf{3r-2r=16-6}\\\\\longrightarrow\bf{r=10\:years}$

Thus;

The present age of son's will be r = 10 years.

The present age of father's will be (3r+3) =[3(10)+3] = [30+3] = 33 years.