Math, asked by nandinikashyap102, 1 year ago

the age of the father is 3 years more than 3 times the age of the son. three yrs hence the age of the father will be 10yrs more than twice the age of the son. their present age in years are

Answers

Answered by Shreya1429
4
Let the present age of son be x.
Father's age = 3+3x
After 3 years,
Age of son = x+3
Father's age = 3+3x+3=6+3x
According to the question,
6+3x= 10+2(x+3)
6+3x=10+2x+6
x=10
Son's present age is 10.
Father's present age is 3+3x
=3+3×10
3+30
=33.
Hope it helps:)
Answered by harshitamadan
2

Let the age of son be x
Father's age =3+3x
ATQ
10+2(x+3)=6+3x
10+2x+6=6+3x
10=x
son's age - 10 yrs
father's age - 33 yrs
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