Question

The age of the father is 40 years while his son's age is 10 years. After how many years will the age of
the father be twice the son's age?​

Answer 1

Answer:

20 years

Step-by-step explanation:

The difference of present ages= 40yrs-10yrs=30yrs

Let the age of father be 2x yrs when he is twice the age of his son. At that time his son's age will be x years. The difference between their ages at that time will be 2x-x= x years

Since the age difference of two people at any time remains the same, their difference (that is x years) will be 30 years only.

So x = 30 years.

If son's present age is 10 yrs and and later he will be 30 years old, so it will happen after 30 yrs-10yrs = 20 years

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Answer 2

The father's age will be twice the son's age after 20 years.

Given,

The age of the father is 40 years.

The age of the son is 10 years.

To Find,

After how many years will the father's age be twice the son's age?

Solution,

The difference of present ages= 40yrs-10yrs=30yrs

Let the age of the father be 2x yrs when he is twice the age of his son.

his son's age will be x years.

The difference between their ages at that time will be 2x-x= x years

Since,

the age difference between father and son will remain the same,

their difference (that is x years) will be 30 years only.

So,

x = 30 years.

If the son's present age is 10 yrs and later he will be 30 years old, so it will happen after 30 yrs-10yrs.

=40+x=2(10+x)

=40+x=20+2x

x = 20.

after 20 years.

The father's age will be twice the son's age after 20 years.

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