Math, asked by lin1105, 22 hours ago

the age of the father is three times the age of the Son if his sum of their ages is 60 years then find their present ages

Pls answer fast

Answers

Answered by neth2444
1

Answer:

age of son: 15

age of father: 45

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Step-by-step explanation:

first, we will put this in numerical form:

lets say that a is the age of the father and b is the age of the son. then,

a=3b

a+b=60

now, we can substitute a with 3b as a=3b.

3b+b = 60

4b = 60

b = 60/4

b = 15

hence, the age of the son is 15.

a = 3b = (3x15) = 45

hence, the age of his father is 45.

Answered by nagapranav36
1

Step-by-step explanation:

Let us assume the age of the son is x.

So, the father's age will be 3x.

The ratio of the son: father will be x: 3x.

x + 3x = 4x (Parts)

\frac{60}{4} = 15 years (1 part)

Son's age: x = 15 years.

Father's age: 3x = 3 * 15

                           = 45 years.

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