Math, asked by prettygirl14, 11 months ago

The age of the father is thrice the sum of ages of his three children. After 3 years his age will be only double of the sum of ages of his three children. Find the present age of the father​.
Step-by-step explanation

Answers

Answered by Anonymous
34

Answer:45

Step-by-step explanation:

Let the sum of the ages of his three sons be X

So the father's age will be 3x

As given, after three years his age will only be twice the sum of his children

So after three years the father's age will be 2(X+9)*

X+9 because three years are added to each sons age.

So the equation formed is 3x+3=2(x+9)

3x+3=2x+18

X=15

The father's age is equal to 3x= 45

HOPE IT HELPS


Anonymous: Welcome
Answered by nehakumari8084675958
4

Answer:

Let the son's age be x

Then , according to the condition,

father's age =3x+3

3 years later:

Son's age =x+3

Father's age =3x+3+3=3x+6

According to the condition given ,

3x+6=10+2(x+3)

3x+6=10+2x+6

x=10

Thus , the son's present age is 10 years and the father's age is

3x+3=3×10+3=33 years.

Similar questions