Question

The age of the father is twice that of his elder son. Ten years hence, the age of the father will be 3 times that of the younger son. If the difference of ages of two sons is 15 years, find the age of the father.

Answer 1

let elder son's age be x

Then, father's age = 2x

y = younger son's age =(x-15)

10 years later

2x+10=3(x-15+10)

2x+10=3(x-5)

3x-2x=25

x=25

y=10

Therefore, father's age = 50

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Answer 2

Answer:

25 years

Step-by-step explanation:

Let the age of elder son be x

Let the age of younger son be y

We are given that The age of the father is twice that of his elder son.

Age of father = 2x

Age of father after 10 years = 2x+10

Age of younger son after 10 years = y+10

Ten years hence, the age of the father will be 3 times that of the younger son.

So, $2x+10=3(y+10)$ ---A

The difference of ages of two sons is 15 years

So, x-y = 15 -- B

Solve A and B

Substitute the value of x form B in A

$2(15+y)+10=3(y+10)$

$y=10$

Substitute the value of y in B

x-10 = 15

x= 15+10 = 25

Hence  the age of the father is 25 years