Question

The age of the father is twice the sum of the age of his 2 children. After 20 years, his age will be equal to the sum of age of his children. Find the age of the father.

Answer 1

Answer:

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Answer 2

☣ Qᴜᴇsᴛɪᴏɴ ☣

➥ The age of the father is twice the sum of the age of his 2 children. After 20 years, his age will be equal to the sum of age of his children. Find the age of the father.  

⛦ Aɴsᴡᴇʀ ⛦

➥ The age of the father is 40 years  

☄ Gɪᴠᴇɴ ☄

➤ Age of father = x

➤ Age of son = y  

⚛ Tᴏ Fɪɴᴅ ⚛

➤ The age of the father = ?  

❏ According To Given Question

↗ Let the present ages of children be x years and y years respectively.  

Then, the present age of the father is twice the sum of the ages of his 2 children = 2(x + y) ----(i)  

His children's ages after 20 years will be (x + 20) years and (y + 20) years.  

Father's age after 20 years will be [2(x + y) + 20] years.  

Then,  

⟾ (x + 20) + (y + 20)  

⟾ 2(x + y) + 20  

⟾ x +y + 40

⟾ 2x + 2y + 20  

⟾ 40 - 20 = 2x + 2y - y

∴ x +y = 20  

⤵ Putting the value of (x + y) in equ (i), we get

⟾ 2(x + y) = 2(20) = 40 years

Hence, the present age of the father is 40 years.