the age of the father is twice the sum of the ages of his two children .after 20 years his age will be equal to the sum ofthe ages of his children .find theage of the father
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Answered by
125
Hi friend,
Let the age of the father = x years
Let the sum of ages of his sons = y years
According to question,
x = 2y-------(1)
Again,
x +20 = y + 40(adding 20 to ages of both the sons)
From (1),
2y+20=y+40
y = 20
-x = 40
Hence,age of father = 40 years.
Hope it helps....Cheers...
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Thanks.
Let the age of the father = x years
Let the sum of ages of his sons = y years
According to question,
x = 2y-------(1)
Again,
x +20 = y + 40(adding 20 to ages of both the sons)
From (1),
2y+20=y+40
y = 20
-x = 40
Hence,age of father = 40 years.
Hope it helps....Cheers...
If you understood from it well,then please please mark as the brainliest.
Thanks.
Answered by
3
Answer:the present age of father is 40 years
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