The age of the father is twice the sum of the ages of his two children.After 20 years ,his age will be equal to the sum of the ages of his children.Find the age of father.
Answers
Answer:
The father's age is 40 years.
Step-by-step explanation:
Let the father's age be x years and the sum of ages of 2 children be y years.
As per the question,
x=2y.....(1)
After 20 years,
x+20=y+20+20
⇒
x+20=y+40
⇒
x=y+20.....(2)
Equating (1) & (2),
y = 20
Substituting y = 20 in equation (1), we get
x = 40
Hence, the father's age is 40 years.
Answer:
The age of the father = 40 years
Step-by-step explanation:
Given,
The age of the father is twice the sum of the ages of his two children
The age of the father after 20 years is equal to the sum of the ages of his two children
To find,
Age of the father
Solution:
Let the age of the father be 'x' and the sum of the ages of his two children be 'y'
From the given statement
The age of the father is twice the sum of the ages of his two children, we get
x = 2y ------------------(1)
After 20 years
The age of the father = x+20
Sum of the ages of the two children = y +40
From the given statement,
The age of the father after 20 years is equal to the sum of the ages of his two children, we get
x+20 = y +40
x = y +40 -20 = y +20
x = y+20 ----------------(2)
Comparing equations (1) and (2) we get
2y = y +20
y = 20
From equation(1)
x = 2y = 2×20 = 40
∴The age of the father = 40 years
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