The age of the father is twice the sum of the ages of his two children.after 20 years his age is equal to the sum of the ages of his children .what is father ages
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Answered by
11
HELLO.....FRIEND!!
THE ANSWER IS HERE,
Let the age of the father be x.
And age of his 2 sons be y & z.
From the question,
=> x=2 (y+z)
After 20years,
=> x+20 = y+20+z+20
=> x+20= y+z+40
=> x=x/2+40-20
=> x/2=20
=> x=40years.
:-)Hope it helps u.
THE ANSWER IS HERE,
Let the age of the father be x.
And age of his 2 sons be y & z.
From the question,
=> x=2 (y+z)
After 20years,
=> x+20 = y+20+z+20
=> x+20= y+z+40
=> x=x/2+40-20
=> x/2=20
=> x=40years.
:-)Hope it helps u.
Answered by
8
Hi Friend !!!
====================
let the age of father be x
and age of sons be y&z
x = 2(y+z)
according to question,
x+20 = y+20+x+20
x +20 = z+y+40
x +20 = x/2+40
x-x/2 = 40-20
x/2 = 20
x= 40
hope it helps u:-)
====================
let the age of father be x
and age of sons be y&z
x = 2(y+z)
according to question,
x+20 = y+20+x+20
x +20 = z+y+40
x +20 = x/2+40
x-x/2 = 40-20
x/2 = 20
x= 40
hope it helps u:-)
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