The age of the father is twice the sum of the ages of his two children. After 20 years his age will be equal to sum of the ages of his children. Find his present age.
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let age of 1 child be x . and other child be y .
So current age of father would be 2(x+y)
After 20 years .
1st son age = x+20
2nd son age =y+20
father age = x+y+40
2(x+y)+20=x+y+40
20=x+y
current father age = 40
So current age of father would be 2(x+y)
After 20 years .
1st son age = x+20
2nd son age =y+20
father age = x+y+40
2(x+y)+20=x+y+40
20=x+y
current father age = 40
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