The age of the man is 4 times of his son.calculate the age of the man 5years ago ,the age of his son is x years
isha3177:
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son age = x
Man age = 4x
Hence, 5 yrs ago, man age = 4x-5
Son age 5 yrs ago = x-5
Hence ,
4x-5 = 7 (x-5)
4x -5= 7x - 35
3x = 30
x = 10
Son present age = 10 yrs
Man present age = 40 yrs
Son age 5 yrs ago = 5 yrs
Man age 5 yrs ago = 35 yrs
Man age = 4x
Hence, 5 yrs ago, man age = 4x-5
Son age 5 yrs ago = x-5
Hence ,
4x-5 = 7 (x-5)
4x -5= 7x - 35
3x = 30
x = 10
Son present age = 10 yrs
Man present age = 40 yrs
Son age 5 yrs ago = 5 yrs
Man age 5 yrs ago = 35 yrs
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let age of son be x
then age of man 5yrs ago is 4x-5
then age of man 5yrs ago is 4x-5
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