Math, asked by shashu11, 1 year ago

The age of the man is 4 times of his son.calculate the age of the man 5years ago ,the age of his son is x years


isha3177: no
littyissacpe8b60: yes it comes 3x
littyissacpe8b60: you check it
littyissacpe8b60: what you go as answer?
littyissacpe8b60: * got
littyissacpe8b60: In my view it should be 3x
Arushisin: It cannot be 3x anyhow
littyissacpe8b60: ok let me tell you
littyissacpe8b60: hey question is incomplete. I checked the question. The age of man 5years ago was 7 times of his son
littyissacpe8b60: So correct the answer with that

Answers

Answered by Arushisin
2
son age = x
Man age = 4x
Hence, 5 yrs ago, man age = 4x-5
Son age 5 yrs ago = x-5
Hence ,
4x-5 = 7 (x-5)
4x -5= 7x - 35
3x = 30
x = 10
Son present age = 10 yrs
Man present age = 40 yrs
Son age 5 yrs ago = 5 yrs
Man age 5 yrs ago = 35 yrs

isha3177: tell me fast
Arushisin: See the answer. I have already corrected it.
sony2006: now the equation is 7x+5
Arushisin: You are going wrong. Try to understand my solution.
sony2006: oh sorry that's not the equate
sony2006: sorry equation
sony2006: ya i understood your solution
sony2006: if you don't mind can i ask you a question
Arushisin: Yup
Arushisin: You can ask.
Answered by Anonymous
0
let age of son be x
then age of man 5yrs ago is 4x-5
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