Math, asked by srishtityagi08, 10 months ago

The age of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The ages of Cathy and Dharam differ by 30 years. Represent the situation graphically. plz answer fast

Answers

Answered by pratikshaharshad74
0

Step-by-step explanation:

The difference between the ages of Biju and Ani is 3 years.

Either Biju is 3 years older than Ani or Ani is 3 years older than Biju.

However, it is obvious that in both cases, Ani’s father’s age will be 30 years more than that of Cathy’s age.

Let the age of Ani and Biju be x and y years respectively.

Therefore,

age of Ani’s father, Dharam = 2 × x = 2x years and the age of Biju’s sister Cathy y/2 years

By using the information given in the question,

Case (I):

When Ani is older than Biju by 3 years, x − y = 3 ………………….(1)

2x – y/2 = 30

4x – y = 60 ————(2)

Subtracting (1) from (2)

3x = 60 – 3 = 57

x = 57/3 = 19

Therefore, age of Ani = 19 years

And age of Biju = 19 − 3 = 16 years

Answered by MysteriousAryan
0

Answer:

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Let the ages of Ani be A

Let the age of Biju be B

Hence, the age of Dharam = 2 x A = 2A yrs.

The age of Biju sister Ani B/2 yrs

As per the given conditions will solve

Case (i)

When Ani is older than that of Biju

A – B = 3 – – – – – – – – (1) {older by 3 years}

2A−B/2 = 30

4A – B = 60 – – – – – – – – – – – (2)

By subtracting the equations (1) and (2) we get,

3A = 60 – 3 = 57

A = 57/3 = 19

The age of Ani = 19 yrs

The age of Biju is 19 – 3 = 16 yrs.

Case (ii)

When Biju is older than Ani,

B – A = 3 – – – – – – – – – (1) {older by 3 years}

2A − B/2 = 30

4A – B = 60 – – – – – – – – – (2)

Adding the equation (1) and (2) we get,

3A = 63

A = 21

Answer

The age of Ani is 21 yrs

The age of Biju is 21 + 3 = 24 yrs.

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