Question

The age of two friends Namami and Shivu differ by 3 years. Namami's father Rohit is twice as old as Shivu and Shivu is twice as old as his sister Lalitya. The ages of Lalitya and Dharam differ by 30 years. Find the ages of Namami and Shivu.​

Answer 1

HeRe IS UR AnS:

Let the age of Namami and Shivu be x and y respectively.

Then according to the question-

x−y=3..........(i)

Rohit is twice the age of Namami

Hence, age of Dharam =2x

Age of Lalitya is half the age of shivu

Then age of Lalitya = 2y

Then according to the question

2x− 2y=30

⇒4x−y=60......(ii)

Subtracting (ii) from (i)

⇒x−y−4x+y=3−60

⇒−3x=−57

⇒x= −3−57

=19

Substitute the vale of x in (i)

⇒19−y=3

⇒−y=−16

⇒y=16

∴ Age of Namami=19 years and age of shivu =16 years.

STudY WeLL...

Answer 2

Correct Question :-

The age of two friends Namami and Shivu differ by 3 years. Namami's father Rohit is twice as old as Shivu and Shivu is twice as old as his sister Lalitya. The ages of Lalitya and Rohit differ by 30 years.

To find :-

The ages of Lalitya and Rohit.

Solution :-

Let the age of Namami be x and Shivu be y

The age of two friends Namami and Shivu differ by 3 years.

• x - y = 3 ---(i)

Namami's father Rohit is twice as old as Shivu.

• Age of Rohit = 2x

Shivu is twice as old as his sister Lalitya.

According to given condition

→ Shivu's age = y

• Lalitya's age = y/2

The ages of Lalitya and Dharam differ by 30 years.

→ Rohit's age - Lalitya's age = 30

→ 2x - y/2 = 30

→ 4x - y/2 = 30

→ 4x - y = 60 ------(ii)

Subtract both equations

→ x - y - (4x - y) = 3 - 60

→ x - y - 4x + y = - 57

→ - 3x = - 57

→ x = 57/3 = 19

Putting the value x in eqⁿ (i)

→ x - y = 3

→ 19 - y = 3

→ y = 19 - 3

→ y = 16

•°• Namami's age = 19 years

•°• Shivu's age = 16 years

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