Question

The age of two friends Namami and Shivu differ by 3 years. Namami's father Rohit is twice as old as Shivu and Shivu is twice as old as his sister Lalitya. The ages of Lalitya and Dharam differ by 30 years. Find the ages of Namami and Shivu.​

yo pratham chacha

whatsup...​

Answer 1

$\huge{ \boxed{ \bold \red{A}}}{ \boxed{ \bold \green{N}}}{ \boxed{ \bold \blue{S}}}{ \boxed{{{ \bold{W}}}}}{ \boxed {\bold \pink{E}}}{ \boxed {\bold \purple{R}}}$

Let the age of Namami be x and Shivu be y

The age of two friends Namami and Shivu differ by 3 years.

• x - y = 3 ---(i)

Namami's father Rohit is twice as old as

Shivu.

• Age of Rohit = 2x

Shivu is twice as old as his sister Lalitya.

According to given condition

→ Shivu's age = y

• Lalitya's age = y/2

The ages of Lalitya and Dharam differ by

30 years.

→ Rohit's age - Lalitya's age = 30

→ 2x - y/2 = 30

→ 4x - y/2 = 30

→ 4x - y = 60 - -(ii)

Subtract both equations

→x-y-(4x - y) = 3 - 60

→x - y - 4x + y = -57

→-3x = -57

→x = 57/3 = 19

Putting the value x in $eq^n$ (i)

→x - y = 3

→ 19 - y = 3

→y=19-3

→y = 16

• Namami's age = 19 years

• Shivu's age = 16 years

Answer 2

Answer:

Let the age of Namami be x and Shivu be y

The age of two friends Namami and Shivu differ by 3 years.

x - y = 3 ---(i)

Namami's father Rohit is twice as old as  Shivu.

Age of Rohit = 2x

Shivu is twice as old as his sister Lalitya.

According to given condition  

→ Shivu's age = y  

Lalitya's age = y/2

The ages of Lalitya and Dharam differ by

30 years.

→ Rohit's age - Lalitya's age = 30

→ 2x - y/2 = 30

→ 4x - y/2 = 30

→ 4x - y = 60 - -(ii)

Subtract both equations

→x-y-(4x - y) = 3 - 60

→x - y - 4x + y = -57  

→-3x = -57  

→x = 57/3 = 19  

Putting the value x in  (i)

→x - y = 3

→ 19 - y = 3  

→y=19-3  

→y = 16

Namami's age = 19 years

Shivu's age = 16 years

Step-by-step explanation:

thanks..