Question

The age of two girls together is 15 years.one is 11 year older than the other. what is the age of younger one?

Explain the answer

Answer 1

Answer:

Age of the younger girl is 4 years

Explanation:

Given

• Sum of ages of two girls is 15 years
• One is 11 year older than the other

To Find

• What's the age of the younger girl.

Solution

Let age of younger girl = x

Age of older girl = x + 11

According to the Question

Age of younger girl + Age of older girl = 15

⟹ ( x ) + ( x + 11 ) = 15

⟹ x + x + 11 = 15

⟹ 2x + 11 = 15

⟹ x = 15 - 11

⟹ x = 4

Age of the younger girl = x = 4 years.

Answer 2

Given -

• The age of two girls together is 15 years.

• One is 11 year older than the other.

To find -

• Age of younger one.

Solution -

In the question, we are provided, with the sum of ages of 2 girls, and one girl is elder than second one by 11 years, so first we will write the common ratio, then we will make the linear equation, then we will find the age of younger one.

So -

Let the age of younger one be x

Other girl is elder than her by 11 yrs, so x + 11

Now -

We will make a linear equation out of it, and then, we will take out the value of x, that is going to be the age of the younger one.

On substituting the values -

$\longrightarrow$ x + (x + 11) = 15

$\longrightarrow$ 2x + 11 = 15

$\longrightarrow$ 2x = 15 - 11

$\longrightarrow$ 2x = 4

$\longrightarrow$ x = $\sf\cancel{\dfrac{4}{2}}$

$\longrightarrow$ x = 2 years

At the end -

Age of younger one is 2 yrs

Age of elder one is x + 11 = 2 + 11 = 13 yrs

Verification -

For verification, we will add up, both the age of younger and elder one.

$\longrightarrow$ 2 + 13 = 15

$\longrightarrow$ 15 = 15

Hence, verified

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