Question

The age of two person differ by 16 years if 6 years ago, the elder one be 3 times as old as the younger one ,find their present agea.

Answer 1

here's your answer....

Answer 2

Answer :

The present ages of younger one and elder one are 14 years and 30 years respectively.

Explanation :

Given : Ages of two persons differ by 16 years. If 6 years ago the elder one will be three times as older as the younger one.

To find : Present ages of them.

Soultion :

Let the age of elder one be x years

Let the age of the younger one be y years

Difference of age between them = 16 years

=> x - y = 16

x = 16 + y ------- eq(1)

6 years ago:

The age of elder one = (x - 6) years

The age of younger one = (y - 6) years

According to the question:

(x - 6) = 3(y - 6)

16 + y - 6 = 3(y - 6)

10 + y = 3y - 18

3y - y = 10 + 18

2y = 28

y = 28/2

y = 14

Subtitute y = 14 in eq(1)

x = 16 + 14

x = 30

So the present ages of younger one and elder one are 14 years and 30 years respectively.