Math, asked by kirtikhubani387, 5 months ago

the age of two persons are in the ration 5:7. eighteen years ago their ages were in the ratio 8:13 . find there present ages
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Answers

Answered by sakash20207
1

Answer:

I DONT NOW THIS BRO PLEASE ASK SOMEBODY.

Answered by tennetiraj86
0

The present ages of two persons are

45 years and 63 years

Given:-

The age of two persons are in the ration 5:7. eighteen years ago their ages were in the ratio 8:13 .

To find:-

find there present ages

Solution:-

The ratio of ages of two persons =5:7

Let they be 5X and 7X

18 years ago their ages =(5X-18) and (7X-18) years

Ratio of their ages 18 years ago=8:13

=>(5X-18):(7X-18)=8:13

=>(5X-18)/(7X-18)=8/13

applying cross multiplication then

=>13(5X-18)=8(7X-18)

=>65X-234=56X-144

=>65X-56X=-144+234

=>9X=90

=>X=90/9

=>X=10

5X=5×9=45

7X=7×9=63

Answer:

The present ages of two persons are 45 years and 63 years

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