Question

the agent angle of a parallelogram are 4x-7 and 6x-3.find the angle of the parallelogram​

Answer 1

Given :-

the adjacent angles of the parallelogram are (4x - 7)° and (6x - 3)°

we know that, the sum of two adjacent angles in a parallelogram = 180°

therefore (4x - 7)° + (6x - 3)° = 180°

➡ 4x - 7 + 6x - 3 = 180°

➡ 10x - 10 = 180°

➡ 10x = 180 + 10

➡ x = 190/10

➡ x = 19°

the two adjacent angles are :-

• 4x - 7 = 4(19) - 7 = 69°

• 6x - 3 = 6(19) - 3 = 111°

we also know that, opposite angles of a parallelogram are equal.

hence, all the angles of the parallelogram are 69°, 111°, 69° and 111°

Answer 2

$\huge\underline{\mathfrak{ANSWER :-}}$

$\sf{Adjacent \:\:angle\:\: of \:\:parallelogram \:\:are (4x-7)° and (6x-3)°}$

$\huge{\mathfrak{A.T.Q}}$

$\huge{\underline{\mathfrak{step \:\:by \:\:step\:\: explaination}}}$

$\sf{(4x - 7)° + (6x - 3)° = 180°}$

$\sf{10x - 10) = 180°}$

$\sf{10x = 180 + 10}$

$\sf{10x = 190}$

$\sf{x = 19°..........<strong>[</strong><strong>Answer</strong><strong>]</strong>}$

Hence, the first angle = 69°

Second angle = 111°

we know that the adjacent angle of parallelogram are equal.

So, the third angle = 69°

Fourth angle = 111°