the ages of 2 person differ by 16 year. If 6 year ago, the elder one be 3 time as old as younger one, find their present age
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younger one's age = 14
elder one's age = 30
I hope it's helpful
elder one's age = 30
I hope it's helpful
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Considering the age of the person A (smaller)to be x.
Age of person B(elder)= 16-x
6 years ago,
Age of person A=x-6
Age of person B= 16-x-16
According to the given question,
Which states that the elder one will be 3 times as the smaller one after 6 years the correct equation is:
3(x-6)=16-x-6
3x-18=10-x
3x+x=10+18
4x=28
x=28/4
x=7
Hence we conclude that the age of the younger person is x= 7years n the age of the elder person is 16-x= 16-7=9
Hope this answer helps u!!! Plz mark as brainliest if u think it was worth it!!!
Age of person B(elder)= 16-x
6 years ago,
Age of person A=x-6
Age of person B= 16-x-16
According to the given question,
Which states that the elder one will be 3 times as the smaller one after 6 years the correct equation is:
3(x-6)=16-x-6
3x-18=10-x
3x+x=10+18
4x=28
x=28/4
x=7
Hence we conclude that the age of the younger person is x= 7years n the age of the elder person is 16-x= 16-7=9
Hope this answer helps u!!! Plz mark as brainliest if u think it was worth it!!!
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