The ages of A and B are in ratio of 8:3 six years hence the ages will be in ratio of 9:4 .Find the present age
Answers
Step-by-step explanation:
small \blue {Let's \: the \: ages \: of \: A \: and \: B \: be \: a}Let
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stheagesofAandBbea
\small \blue { After \: six \: years : }Aftersixyears:
\small \sf {Agè \: of \: A = 8a + 6}Ag
e
ˋ
ofA=8a+6
\small \sf {Agè \: of \: B = 3a + 6}Ag
e
ˋ
ofB=3a+6
After six years their age :-
\small \sf {(8a+6)/(3a+6) = 9/4 }(8a+6)/(3a+6)=9/4
\small \sf {4(8a+6) = 9 (3a + 6)}4(8a+6)=9(3a+6)
\small \sf {32a + 24 = 27a + 54}32a+24=27a+54
\small \sf {32a - 27 a= 54-24}32a−27a=54−24
\small \sf {5a = 30}5a=30
\small \sf {a = 6}a=6
Age of A = 8 × 6 = 48
Age of B = 3 × 6 = 18
{:}\longrightarrow:⟶ \huge \fbox {A \: = 48 years}
A = 48 years
{:}\longrightarrow:⟶ \huge \fbox {B \: = 18 years}
B = 18 years
ofA=8a+6
\small \sf {Agè \: of \: B = 3a + 6}Ag
e
ˋ
ofB=3a+6
After six years their age :-
\small \sf {(8a+6)/(3a+6) = 9/4 }(8a+6)/(3a+6)=9/4
\small \sf {4(8a+6) = 9 (3a + 6)}4(8a+6)=9(3a+6)
\small \sf {32a + 24 = 27a + 54}32a+24=27a+54
\small \sf {32a - 27 a= 54-24}32a−27a=54−24
\small \sf {5a = 30}5a=30
\small \sf {a = 6}a=6
Age of A = 8 × 6 = 48
Age of B = 3 × 6 = 18
{:}\longrightarrow:⟶ \huge \fbox {A \: = 48 years}
A = 48 years
{:}\longrightarrow:⟶ \huge \fbox {B \: = 18 years}
B = 18 years
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