Math, asked by sandy1926, 11 months ago

the ages of A and B are in the ratio 2:3.six years ago their ages were in the ratio3:5.find their present ages​

Answers

Answered by Geetu18
5

Answer:

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Attachments:
Answered by paraschuri2005
0

Step-by-step explanation:

Let the age of A be x years & B be y years

According to 1st condition

x/y=2/3

3x=2y

3x-2y=0 -(1)

Before 6 years,

Age of A =(x-6) years & B=(y-6) years

According to second condition,

x-6/y-6=3/5

5(x-6)=3(y-6)

5x-30=3y-18

5x-3y=-18+30

5x-3y=12 -(2)

Multiplying eqn (1) by 3 & (2) by 2

9x-6y=0 -(3)

10x-6y=24 -(4)

Subtracting eqn (3) from (4)

10x-6y=24

-9x+6y=0

x=24

Substituting x=24 in eqn (1)

3(24)-2y =0

72-2y=0

72=2y

y=36

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