the ages of A and B are in the ratio 2:3.six years ago their ages were in the ratio3:5.find their present ages
Answers
Answered by
5
Answer:
please mark me brainliest
Attachments:
Answered by
0
Step-by-step explanation:
Let the age of A be x years & B be y years
According to 1st condition
x/y=2/3
3x=2y
3x-2y=0 -(1)
Before 6 years,
Age of A =(x-6) years & B=(y-6) years
According to second condition,
x-6/y-6=3/5
5(x-6)=3(y-6)
5x-30=3y-18
5x-3y=-18+30
5x-3y=12 -(2)
Multiplying eqn (1) by 3 & (2) by 2
9x-6y=0 -(3)
10x-6y=24 -(4)
Subtracting eqn (3) from (4)
10x-6y=24
-9x+6y=0
x=24
Substituting x=24 in eqn (1)
3(24)-2y =0
72-2y=0
72=2y
y=36
Similar questions