Question

The ages of A and B are in the ratio 4:3.After 6 years there ages will be in the ratio 11:9. find there present age......

Answer 1

refer to the attached file

Answer 2

$\underline {\blue { At \: present : }}$

$Age \: of \: A = 4x \: years$

$Age \: of \: B = 3x \: years$

$\underline {\pink { After \:6 \: years: }}$

$Age \: of \: A = (4x+6) \: years$

$Age \: of \: B =( 3x+6) \: years$

/* According to the problem given */

$\frac{(4x+6)}{(3x+6)} = \frac{11}{9}$

$\implies 9(4x+6) = 11(3x+6)$

$\implies 36x + 54 = 33x + 66$

$\implies 36x - 33x = 66 - 54$

$\implies 3x = 12$

$\implies x = \frac{12}{3}$

$\implies x = 4$

Therefore.,

$\red{ Present \:age\:of \:A } \\= 4x\\= 4\times 4 \\\green {= 16 \: years }$

$\red{ Present \:age\:of \:B} \\= 3x\\= 3\times 4 \\\green {= 12\: years }$

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