Question

THE AGES OF A AND B ARE IN THE RATIO 5:7 . AFTER 5 YEARS , THE RATIO WILL BE 5:6 . FIND THE PRESENT AGES



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Answer 1

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Let A present age is a.

Let B present age is b.

For,

a:b = 5:6

Let the common multiple be c. there fore,

a=5c and b=6c and

A age fine years from now is a+5

B age fine years from now is b+5

hence,

(a+5):(b+5)=6:7

⇒

6c+5

5c+5

=

7

6

⇒ 35c+35=36c+30

hence the c=5

hence the present age of A is 25

and B is 30

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Answer 2

GIVEN:-

Ages of a and b are in ratio = 5:7

5 year later, ages in ratio = 5:6

Let, the present ages be x and y ,

ATQ,

x:y = 5:7

or,

x/y = 5/7-------------------(1)

After, 5 years =>

(x+5):(y+5)= 5:6

or,

(x+5)/(y+5)=5/6---------(2)

Solving eqn(1) and (2):-

from (1):-

x=5/7*y

now, putting it on eqn(2)

=>(5/7*y+5)/(y+5)=5/6

=>6(5/7*y+5)=5(y+5)

=>30/7*y+30=5y+25

=>30/7*y-5y=25-30

=>(30y-35y)/7=-5

=>-5y/7=-5

=>5y=35

=>y=7

putting y in eqn(1)

x/y=5/7

=>x/7=5/7

=>x=5

•°• x= 5, y=7

Hence, present age =5*5=25

and 7*7=49

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