Math, asked by krs62, 3 months ago

The ages of A and B are in the ratio 5 : 7. Eight years ago, their ages were in the ratio 7 : 13. Then the present age of B is​

Answers

Answered by 917998
2

Answer:

21 years

Step-by-step explanation:

Let the present age of A be 5x and B be 7x.

Now,

there ages 8 yrs ago = (5x-8) / (7x-8) = 7/13

65x - 104 = 49x - 56

16x = 48

x=3

The age of the A = 5*3 = 15 yrs

The age of B = 7*3 = 21 yrs.

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