the ages of A and B are in the ratio 5:7, five
years ago their age were in the ratio 7:13,find their age
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Given :
- Ratio of the age of A and B = 5 : 7
- Ratio of their ages before 5 years = 7 : 13
To find :
- Present age of A and B.
Solution :
Let,
- Present age of A = 5x years
- Present age of B = 7x years
Their ages ago five years :-
→ Age of A = 5x - 5 years
→ Age of B = 7x - 5 years
According to the question,
⇒ (5x - 5)/(7x - 5) = 7/13
⇒ 13(5x - 5) = 7(7x - 5)
⇒ 65x - 65 = 49x - 35
⇒ 65x - 49x = - 35 + 65
⇒ 16x = 30
⇒ x = 30/16
⇒ x = 1.875
Substituting the value of 'x' in the present ages of A and B :-
→ Present age of A = 5x
→ Present age of A = 5(1.875)
→ Present age of A = 9.375 years
→ Present age of B = 7x
→ Present age of B = 7(1.875)
→ Present age of B = 13.125 years
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