Math, asked by ilonisaiteja35, 1 year ago

The ages of A and B are in the ratio 7:5 After ten year ,the ratio of their ages will be9:7.The present age of B is

Answers

Answered by Anonymous
39

Answer:

here your answer.....

25 year's

Step-by-step explanation:

let the ages of

a and b be 7x,5x

ATQ

7x+10/5x+10=9/7

7(7x+10) =9(5x+10)

49x+70=45x+90

4x=20

x=5

therefore the present age of B is

5x=5*5=25 year's

Answered by Anonymous
44

\textbf{\underline{\underline{According\:to\:the\:Question}}}

Assumption

Age of A be 7p

Age of B be 5p

Situation :-

(7p + 10) : (5p + 10) = 9 : 7

\tt{\rightarrow\dfrac{7p+10}{5p+10}=\dfrac{9}{7}}

7(7p + 10) = 9 (5p + 10)

49p + 70 = 45p + 90

49p - 45p = 90 - 70

4p = 20

\tt{\rightarrow p=\dfrac{20}{4}}

p = 5

{\boxed{\sf\:{Present\;age\;of\;A=7p}}}

= (7 × 5)

= 35 years

{\boxed{\sf\:{Present\;age\;of\;B=5p}}}

= (5 × 5)

= 25 years

\Large{\boxed{\sf\:{Present\;age\;of\;B=25}}}

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