the ages of A and B are in the ratio 9:4. Seven years hence, the ratio of their ages will be 5:3. Find their ages using simultaneous equations. please answer very quick. it is very important.
Answers
Given
Answer:
Age of A is 18 years and B is 8 years.
Step-by-step explanation:
Method 1)
The ages of A and B are in the ratio 9:4.
Assume that the age of A is x and B is y.
→ x/y = 9/4
→ 4x = 9y
→ 4x - 9y = 0 ...............(1)
Seven years hence, the ratio of their ages will be 5:3.
Seven years hence:
- Age of A = (x + 7)
- Age of B = (y + 7)
As per given condition,
→ (x + 7)/(y + 7) = 5/3
→ 3(x + 7) = 5(y + 7)
→ 3x + 21 = 5y + 35
→ 3x - 5y = 14 ................(2)
On multiplying (1) with 3 & (2) with 4 we get,
→ 12x - 27y = 0
→ 12x = 27y ...........(3)
→ 12x - 20y = 56
→ 12x = 56 + 20y ........(4)
On comparing (3) & (4) we get,
→ 27y = 56 + 20y
→ 7y = 56
→ y = 8
Substitute value of y in (1)
→ 4x = 9(8)
→ 4x = 72
→ x = 18
Hence, the age of:
- A = x = 18 years
- B = y = 8 years
Method 2)
Assume that the age of A is 9x and B is 4x.
Seven years hence, the ratio of their ages will be 5:3.
Seven years hence:
- Age of A = (9x + 7) years
- Age of B = (4x + 7) years
As per given condition,
→ (9x + 7)/(4x + 7) = 5/3
→ 3(9x + 7) = 5(4x + 7)
→ 27x + 21 = 20x + 35
→ 7x = 14
→ x = 2
Hence, the age of :
- A = 9x = 9(2) = 18 years
- B = 4x = 4(2) = 8 years