Question

The ages of a father and his daughter are in the ratio 7:2.if the sum of their ages was 45 before 9 yrs then find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

Let age be x

Father's age=7x

Daughter's age=2x

before 9 years,

Father's age=7x-9

Daughter's age=2x-9

A/C to ques,

   7x-9+2x-9=45

   9x-18=45

   9x= 63

    x=7

Father's present age=7*7=49

Daughter's present age=7*2=14

Answer 2

7x - 9 + 2x - 9 = 45

9x = 63

x = 7

father age = 7x = 49

daughter age = 2x = 14