The ages of Ajay and Akhil are in the ratio 3 : 4 . Five years ago ratio of their ages
was 2 : 3 . Find their present ages.
Answers
EXPLANATION.
→ Let the age of Ajay be = 3x
→ Let the age of Akhil be = 4x
→ The ages of ajay and akhil are in ratio = 3:4
Five years,ago their age was = 2:3.
→ Let present age of ajay = ( 3x - 5 )
→ Let present age of akhil = ( 4x - 5 )
→ ( 3x - 5 ) / ( 4x - 5 ) = 2/3
→ 3 ( 3x - 5 ) = 2 ( 4x - 5 )
→ 9x - 15 = 8x - 10
→ x = 5
→ Therefore,
→ present age of ajay = 3x = 3(5) = 15 years.
→ present age of akhil = 4x = 4(5) = 20 years.
Question
The ages of Ajay and Akhil are in the ratio 3 : 4. Five years ago ratio of their ages was 2 : 3. Find their present ages.
Solution
Let, the ages of Ajay and Akhil be 3x and 4x
Five years ago, Ajay's age be 3x-5
Five years ago, Akhil's age be 4x-5
ATP
=) 3(3x-5) = 2(4x-5)
=) 9x-15 = 8x-10
=) 9x-8x = 15-10
=) x = 5
Ans:- Present age of Ajay = (3×5) = 15yrs
Present age of Akhil = (4×5) = 20yrs