Math, asked by tanmayranjan2009, 4 hours ago

The ages of Ajay and Bhaskar are in the ratio 5:7 .Five years from now, the ratio of their ages will be 5:6. Find their present ages.
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Answers

Answered by itsmesanyo29
18

 \huge{ \purple{ANSWER:}}

 { \red{Given : }}

The ratio of ajay and bhaskar present ages is 5:7

{ \blue{Solution: }}

So, let there ages be 5x and 7x

After 5 years there ratio will be 5:6

Therefore,

\frac{(5x + 5) }{(7x + 5)}  =  \frac{5}{6}

6(5x + 5) = 5(7x + 5)

(30x + 30) = (35x + 25)

30 - 25 = 35x - 30x

5 = 5x

x =  \frac{5}{5}

x = 1

Therefore,

The present age of ajay is 5x = 5×1 = 5 years

The present age of bhaskar is 7x =7×1 = 7 years

Answered by SANDHIVA1974
1

Given :

The ages of Ajay and Bhaskar are in the ratio 5:7 .

Five years from now, the ratio of their ages will be 5:6 .

To Find :

Present Age of Ajay and Bhaskar .

Solution :

\longmapsto\tt{Let\:Present\:age\:of\:Ajay\:be=5x}

\longmapsto\tt{Let\:Present\:age\:of\:Bhaskar\:be=7x}

After 5 years :

\longmapsto\tt{Age\:of\:Ajay=5x+5}

\longmapsto\tt{Age\:of\:Bhaskar=7x+5}

A.T.Q :

\longmapsto\tt{\dfrac{5x+5}{7x+5}=\dfrac{5}{6}}

\longmapsto\tt{6(5x+5)=5(7x+5)}

\longmapsto\tt{30x+30=35x+25}

\longmapsto\tt{30x-35x=25-30}

\longmapsto\tt{-5x=-5}

\longmapsto\tt{x=\cancel\dfrac{-5}{-5}}

\purple\longmapsto\:\large\underline{\boxed{\bf\blue{x}\pink{=}\red{1}}}

Value of x is 1 .

Therefore :

\longmapsto\tt{Present\:Age\:of\:Ajay=5(1)}

\longmapsto\tt\bf{5\:yrs}

\longmapsto\tt{Present\:Age\:of\:Bhaskar=7(1)}

\longmapsto\tt\bf{7\:yrs}

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