The ages of Alberta and Nelson are in the ratio 5:7 if 18 years ago, their ages were in the ratio 8:13, then present ages
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Answer:
Their present ages is 50 and 70.
Let Ages of two persons is 5x,7x
Eighteen years ago their ages were (5x-18),(7x-18) Their ratio is 8:13 so…
(5x-18)/(7x-18)=8/13
13(5x-18)=8(7x-18)
65x-234=56x-144
65x-56x=234–144
9x=90
x=10
Therefore their ppresent ages will be,
5(10),7(10)
50,70
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