Math, asked by shifajamal, 8 months ago

The ages of Albin and Aleena are in the ratio 4:7, Four years later the sum of
their ages will be 52 years. What are their present ages? *

pls answer pls​

Answers

Answered by ankit060607
1

Answer:

Let the age of Albin be 4x

and the age of Aleena be 7x

After four years,

Age of Albin = 4x +4

Age of Aleena = 7x +4

A.T.Q

4x+4+7x+4=52

11x +8= 52

11x = 52+8

11x =44

x = 44/11

x= 4

Therefore,

age of Albin = 4x = 4×4 = 16 years

age of Aleena= 7x = 7×4 = 28 years

Answered by maharshi51
1

Step-by-step explanation:

Age of Albin : 4x

Age of Aleena : 7x

4 years later

age of Albin : 4x + 4

age of Aleena : 7x + 4

4x + 4 + 7x + 4 = 52

11x + 8 = 52

11x =52-8

11x=44

x=44/11

x=4

Present age of Albin = 4x

4*4

16

Present age of Aleena = 7x

7*4

28

Hope it helps

Mark as brainliest

follow me for such solutions

Attachments:
Similar questions