Math, asked by hayafatma1, 6 months ago

the ages of Anu and Manu are in the ratio 2:3 five years later the sum of the ages will be 60 what are the present ages​

Answers

Answered by sunakat483
0

Answer:

Let the present age of Nuri =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10 ………..(1)

Ten years later,

Age of Nuri =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10 ………..(2)

X–3y=−10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age of Nuri =50 years and age of Sonu =20 years

Step-by-step explanation:

hope this will help you

Answered by harshi0212
0

Step-by-step explanation:

let Anu be 2x and Manu be 3x respectively

sum = 60

A/Q

2x + 3x = 60

5x = 60

x = 12

2x = 2 × 12 = 24

3x = 3 × 12 = 36

Anu = 24 , Manu = 36

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