Math, asked by Anonymous, 5 months ago

the ages of Arpita and Beena are in the ratio 4:7. Eight years ago their ages were in the ratio 1:2. Find their present ages.

Answers

Answered by vashist2007
14
  • present age ratio of Arpita and Beena = 4:7
  • let present age of Arpita = 4x
  • let present age of Beena =7x
  • eight years ago age ratio of Arpita and Beena are 1:2
  • first,

find age of both Arpita and Beena eight years ago

  • eight years ago,

age of Arpita = 4x-8

age of Beena = 7x-8

  • (4x-8):(7x-8) :: 1:2
  • 2(4x-8) = 7x-8
  • 8x-16 = 7x-8
  • 8x-7x = -8+16
  • x = 8

therefore,

present age of Arpita = 4x = 4×8 =32

present age of Beena =7x = 7×8 = 56

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Answered by omkarjena914
2

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