Math, asked by aaliya8830, 1 month ago

the ages of arpita and beena are in the ratio of 4:7 eight years ago there ages where in ratio of 1 :2 find their present age​

Answers

Answered by niharikasnair2005
2

Answer:

Their present ages are 32 and 56

Step-by-step explanation:

Present age ratio of Arpita and Beena = 4:7

Let present age of Arpita = 4x

Let present age of Beena =7x

Eight years ago age ratio of Arpita and Beena are 1:2

first,  we have to find ages of both Arpita and Beena eight years ago,

Eight years ago,

age of Arpita = 4x-8

age of Beena = 7x-8

(4x-8):(7x-8) :: 1:2

2(4x-8) = 7x-8

8x-16 = 7x-8

8x-7x = -8+16

x = 8

therefore,

Present age of Arpita= 4x = 4x8

= 32

Present age of Beena = 7x = 7x8

= 56

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