Question

The ages of David and Matt total 38 years. David’s age plus twice Matt’s
age is 50. Determine David and Matt’s age.

Answer 1

Answer:

AGE OF MATT =12

AGE OF DAVID = 26

Step-by-step explanation:

ATQ

D+M =38 ...i

D+2M=50 ....ii

Subtract eq i from ii

D+2M-( D+M)=50 -38

D+2m-D-M=12

M=12

AGE MATT=12

AGE OF DAVID = D+M =38

= D +12=38

= D=38-12=26

Answer 2

Answer:

David's age = 26 years

And Matt’s age = 12 years

Step-by-step explanation:

Let us assume that the ages of David and Matt be x years and y years respectively.

Given that:

The ages of David and Matt are total 38 years.

→ x + y = 38

→ x = 38 - y

And David’s age plus twice Matt’s age is 50 years.

→ x + 2y = 50

→ x = 50 - 2y

Comparing both the equation:

→ 38 - y = 50 - 2y

→ - y + 2y = 50 - 38

→ y = 12

∴ Matt’s age = 12 years

Substituting the value of y:

→ x = 38 - 12 or x = 50 - 2 × 12

→ x = 26 or x = 50 - 24

→ x = 26 or x = 26

∴ David’s age = 26 years