Question

The ages of Deepa and Sudha are in the ratio 5:8. Five years
later, the sum of their ages will be 75. What are their present
ages?​

Answer 1

Answer:

let the current age of Deepa is 5x years

and the current age of Sudha is 8x years

5 years later ,

5x+5+8x+5=75

=> 13x=75-5-5

=> 13x=65

=> x=65/13

=> x=5

present age of Deepa is 5×5years=25years

present age of Sudha is 8×5years=40 years

Answer 2

Step-by-step explanation:

Given,

Present ages of Deepa and Sudha in the ratio are = 5:8

Let,

The common factor be x

So,

Present age of Deepa and Sudha are = 5x and 8x (respectively)

After 5 years,

Ages of Deepa and Sudha are = 5x+5 and 8x+5 (respectively)

Also said that,

After 5 years sum of their ages will be 75

Therefore,

By the problem,

=> 5x+5 + 8x+5 = 75

=> 5x + 8x + 5 +5 = 75

=> 13x + 10 = 75

=> 13x = 75 - 10

=> 13x = 65

$= > x = \frac{65}{13}$

=> x = 5

So Present Ages,

Deepa = 5x = 5 × 5 = 25 years.

Sudha = 8x = 8 × 5 = 40 years.

Hence,

Present age of Deepa is 25 years and present age of Sudha is 40 years (Ans)