The ages of ena and Heena are in the ratio 7:5. Ten years hence, the ratio of their ages will be 9 7. Find their present ages.
Answers
Answered by
1
hii!!
here's ur answer...
let the present age of RNA and Heena be 7x and 5x.
after ten years their age will be 9x and 7x.
therefore 7x+10+5x+10=9x+7x
12x+20=16x
20=16x-12x
20=4x
x=20/4
x=6
hence, present age of ena=7x
=7×6
=42yrs
present age of Heena=5x
=5×6
=30yrs
hope this helps u...
here's ur answer...
let the present age of RNA and Heena be 7x and 5x.
after ten years their age will be 9x and 7x.
therefore 7x+10+5x+10=9x+7x
12x+20=16x
20=16x-12x
20=4x
x=20/4
x=6
hence, present age of ena=7x
=7×6
=42yrs
present age of Heena=5x
=5×6
=30yrs
hope this helps u...
SUMIT1511:
what pubg???
hiii you don't talk me
players unknown battleground
???
game hai
what you like "pubg"
hmm
hmm2
hey! you don't talk
hiiii you don't talk
Answered by
0
the present age will be
heena-7x
ena-5x
after 10 yrs
heena 9x
ena 7x
ATQ
7x+10/5x+10 =9x+7x
9x(5x+10)=7x(7x+10)
45x^2+90x=49^2+70x
45x^2-49^2=70x-90x
-4x^2=-20x
4x^2=20x
x^2=20x/4=5x
x=
heena-7x
ena-5x
after 10 yrs
heena 9x
ena 7x
ATQ
7x+10/5x+10 =9x+7x
9x(5x+10)=7x(7x+10)
45x^2+90x=49^2+70x
45x^2-49^2=70x-90x
-4x^2=-20x
4x^2=20x
x^2=20x/4=5x
x=
Similar questions