Question

the ages of four brothers of a family are in A p series .The eldest brother age is 17 years and the age difference the eldest and the youngest brother is 9 years. Find the ages of four brothers ... .Its urgent

Answer 1

age is 8 11. 14. 17
divide the difference in 3 equal parts you get 3 years
age of youngest is 17 - 9 =8
2nd one is 8+3=11
3rdone is 11+3=14
4th one is given 17

Answer 2

the ages of four brothers are in AP series show the difference between the age of
1st - 2nd =x
2nd - 3rd = x
3rd - 4th = x
age of first brother = 17 yrs
age of 4th brother = 8 yrs
difference between the ages = 9yrs
age of second brother = 8yrs + 3 yrs
= 11yrs
age of third brother = 11yrs + 3yrs
= 14 yrs