Math, asked by nik111168, 2 months ago

The ages of John and David differ by 16 years. Six years ago, David’s age was thrice as that of John’s.

Find their present ages.

Answers

Answered by souvik2229
4

Step-by-step explanation:

let age of John = x yrs

age of Dravid= x-16 yrs

6 years ago

age of John =(x -6 )yrs

age of David= x-16-6= (x-22 )yrs

David age was thrice of that John's = 3(x -22) yrs

A. T. P

( x -6)= 3(x-22)

x-6 = 3x -66

x-3x = -66+6

-2x = -60

x = 30

therefore age of David= 30 -16 = 14 yrs

age of John = 30 yrs

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