The ages of Leena and and Helena are in ratio 7:5 .ten years hence ratio of their ages will be 9:7 find their present age
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Answered by
2
Hi friend,
Let the present age of Leena and Helena be 7x and 5x respectively .
Age of Leena 10 years hence = 7x+10
Age of Helen 10 years hence = 5x+10
Ratio of ages after 10 years = 9:7= 9/7
A.T.Q
7x+10/5x+10=9/7
by cross multiplication we get,
7(7x+10) = 9(5x+10)
49x+70= 45x+90
49x-45x = 90-70
4x= 20
x = 20/4
x= 5
Present age of Leena =7x = 7× 5= 35 years.
Present age of Helena = 5x = 5×5= 25 years.
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Hope this helped u.
PLZ MARK AS BRAINLIEST....
Let the present age of Leena and Helena be 7x and 5x respectively .
Age of Leena 10 years hence = 7x+10
Age of Helen 10 years hence = 5x+10
Ratio of ages after 10 years = 9:7= 9/7
A.T.Q
7x+10/5x+10=9/7
by cross multiplication we get,
7(7x+10) = 9(5x+10)
49x+70= 45x+90
49x-45x = 90-70
4x= 20
x = 20/4
x= 5
Present age of Leena =7x = 7× 5= 35 years.
Present age of Helena = 5x = 5×5= 25 years.
------------------------
Hope this helped u.
PLZ MARK AS BRAINLIEST....
Answered by
1
let there present age be x and y
now x+10/y+10=9/7 and and x/y=7/5
so x/y=7/5
x=7y/5 now put this in the first eqn
now go with the pic
now x+10/y+10=9/7 and and x/y=7/5
so x/y=7/5
x=7y/5 now put this in the first eqn
now go with the pic
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