Question

the ages of Leena and Heena are in ratio 7:5. 10 years hence,the ratio of their ages will be 9:7.find their present ages

Answer 1

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Answer 2

$\sf{\tiny{\boxed{\bold{Heya \: mate.\: Solution\: below}}}}$

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$<b><u><i><font color = "red">Answer - ↓↓↓</font color></i></u></b>$

♠ $\texttt{Let the present ages of Alina and Heena be 7x and 5x respectively.}$

♠ After 10 years,

Alina's age = 7x + 10

Heena's age = 5x + 10

♠ But, according to the question, after 10 years, their ages will be in ratio 9 : 7.

♠ Then,

$\sf{\frac{7x + 10}{5x + 10} = \frac{9}{7}}$

$\sf{=⟩ 7(7x + 10) = 9(5x + 10)}$

$\sf{=⟩ 49x + 70 = 45x + 90}$

$\sf{=⟩ 49x - 45x = 90 - 70}$

$\sf{=⟩ 4x = 20}$

$\sf{=⟩ x = \frac{20}{4}}$

$\sf{=⟩ x = 5}$

♠ •°• Alina's present age $\sf{= 7x = 7(5) = 35\: years.}$

And, Heena's present age $\sf{= 5x = 5(5) = 25 \:years.}$ ♥

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