Question

the ages of Leena and Heena are in ratio 7:5.ten years hence,the ratio of their ages will be 9:7.find their preent ages.

Answer 1

Hey



Let the ratio constant he x .


Age of Leena be 7x years
Age of Heena be 5x years

After ten years ,

Age of Leena = ( 7x + 10 ) years .
Age of Heena = ( 5x + 10 ) years .

A / q ,

7x + 10 / 5x + 10 = 9 / 7


=> 49x + 70 = 45x + 90
=> 49x -45x = 90 - 70
=> 4x = 20
=> x = 5 .


So ,


Age of Leena = 35 years .
Age of Heena = 25 years .


thanks :)

Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years