Math, asked by kumarisaroj1982, 7 months ago

the ages of leena and heena are in the ratio 7.° ten years hence , the ratio of their ages will be 9.°7 find their ages three years ago ​

Answers

Answered by niishaa
5

Answer:

let Leena's present age be 7x years and Heena's present age be 5x years            

 After 10 years,

Leena's age = 7x+10

Heena's age = 5x+10

7x+10+5x+10 = 9x+7x

20 = 16x-12x

20 = 4x

x = 5

Leena's present age = 7x = 7×5 = 35

Heena's present age = 5×5 = 25

Answered by ItzDeadDeal
3

Answer:

Let Leena's present age be 7x years and Heena's present age be 5x years            

 After 10 years,

Leena's age = 7x+10

Heena's age = 5x+10

7x+10+5x+10 = 9x+7x

20 = 16x-12x

20 = 4x

x = 5

Leena's present age = 7x = 7×5 = 35

Heena's present age = 5×5 = 25

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