the ages of leena and heena are in the ratio 7.° ten years hence , the ratio of their ages will be 9.°7 find their ages three years ago
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Answered by
5
Answer:
let Leena's present age be 7x years and Heena's present age be 5x years
After 10 years,
Leena's age = 7x+10
Heena's age = 5x+10
7x+10+5x+10 = 9x+7x
20 = 16x-12x
20 = 4x
x = 5
Leena's present age = 7x = 7×5 = 35
Heena's present age = 5×5 = 25
Answered by
3
Answer:
Let Leena's present age be 7x years and Heena's present age be 5x years
After 10 years,
Leena's age = 7x+10
Heena's age = 5x+10
7x+10+5x+10 = 9x+7x
20 = 16x-12x
20 = 4x
x = 5
Leena's present age = 7x = 7×5 = 35
Heena's present age = 5×5 = 25
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