Question

The ages of Leena and heena are in the ratio 7:5. Ten years hence, the ratio of their ages will be 9:7. Find their present age.

Answer 1

let the age of leena = 7x
and the age of heena = 5x
ATQ,
7x+10/5x+10=9x/7x
45x+90=49x+70
4x=20
x=5
so age of leena=35 years
and the age of heena=25 years
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Answer 2

Hi friend ,
Let the ages of Leena and Heena be 7x and 5x respectively.
Ten years hence Leena 's age = 7x+10
Ten years hence Heena 's age = 5x+10
A.T.Q
7x+10/5x+10 = 9/7
By cross multiplication we get,
7(7x+10) = 9(5x+10)
49x+70=45x+90
49x-45x= 90-70
4x = 20
x = 20/4
x = 5
Leena's age = 7x = 7×5 = 35 years
Heena's age = 5x= 5×5 = 25 years
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