Math, asked by pr5867266, 10 months ago

The ages of leena and heena are in the ratio 7:5 ten years hence , the ratio of their ages will be 9:7 find their ages three years ago?​

Answers

Answered by Mchatterjee06
2

Answer:

Age of Leena is 32 years and age of heena is 22 years

Step-by-step explanation:

Let leena's age be 7x years and heena's age be 5x years.

10 years hence,

age of leena= 7x+10

age of heena = 5x + 10

according to the problem,

7x+10/5x+10=9/7

or, 49x+70= 45x+90

or, 49x - 45x = 90-70

or, 4x= 20

or, x=20/4

therefore, x= 5

leena's age now=7*5 yrs= 35 years

heena's age now=5*5 yrs= 25 years

3 years ago their ages were,

age of leena= (35-3)yrs= 32 years

age of heena= (25-3) yrs= 22 years

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