Question

The ages of leena and Heena are in the ratio 7:5 ten years hence the ratio of their ages will be 9 :7.find their
present ages

Answer 1

the ratio of their age is 7:5, let the age of Leena and heena 7x and 5x
now after 10 year their age become
7x+10 and 5x+10 and their ratio is 9:7
so, According to question
7x+10÷5x+10 = 9÷7
7(7x+10) = 9(5x+10)
49x+70 = 45x+90
4x = 20
x = 5
hence their age will be 7x = 35 years and 5x = 25 years
I hope it help u
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Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years