Question

the ages of Leena and Heena are in the ratio 7:5. ten years hence the ratio of this is will be9:7. find the present ages.​

Answer 1

Answer:

35,25 years

Step-by-step explanation:

let their age be x

then leena's age= 7x

heena's age= 5x

after 10 years age of-

leena= 7x+10

heena= 5x+10

according to question,

leena's age after 10 years/heena's age after 10 years= 9/7

so, 7x+10/5x+10 = 9/7

= 7(7x+10) = 9(5x+10)        (cross multiplication)

= 49x + 70= 45x + 90

= 49x-45x = 90-70

= 4x= 20

= x= 20/4= 5

then, leena's present age= 7x= 7(5)= 35 years

heena's present age= 5x+5(5)= 25 years

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