Question

the ages of Leena and Heena are in the ratio 7 ratio 5 10 years hence the ratio of their ages will be the ratio 7 find their present ages

Answer 1

Let Leena's present age be 7x years and Heena's present age be 5x years            
 After 10 years,
Leena's age=7x+10
Heena's age=5x+10
7x+10+5x+10=9x+7x
20=16x-12x
20=4x
x=5

Leena's present age=7x=7×5=35
Heena's present age=5×5=25

Answer 2

$\sf{\tiny{\boxed{\bold{Heya \: mate.\: Solution\: below}}}}$

=========================================

$<b><u><i><font color = "red">Answer - ↓↓↓</font color></i></u></b>$

♠ Let the present ages of Alina and Heena be 7x and 5x respectively.

♠ After 10 years,

Alina's age = 7x + 10

Heena's age = 5x + 10

♠ But, according to the question, after 10 years, their ages will be in ratio 9 : 7.

♠ Then,

$\sf{\frac{7x + 10}{5x + 10} = \frac{9}{7}}$

$\sf{=⟩ 7(7x + 10) = 9(5x + 10)}$

$\sf{=⟩ 49x + 70 = 45x + 90}$

$\sf{=⟩ 49x - 45x = 90 - 70}$

$\sf{=⟩ 4x = 20}$

$\sf{=⟩ x = \frac{20}{4}}$

$\sf{=⟩ x = 5}$

♠ •°• Alina's present age $\sf{= 7x = 7(5) = 35\: years.}$

And, Heena's present age $\sf{= 5x = 5(5) = 25 \:years.}$ ♥

=========================================

Thank you... (^_-)